C++ Return Reference To Local Variable
C++ Return Reference To Local Variable. Return i;} will not work because you're returning an alias (a. In a case like this, you should really return a value.
Vector & find1 (string &search_word) // ^^. You should never return a reference or a pointer to a local variable. So the return of the function will be a reference to a (part of) local.
Hence, This Function Returns A Reference Of The Variable Num.
How to return a local variable from a function? C++ returning reference to local variable. You should never return a reference or a pointer to a local variable.
The Return Statement Is Return Num;.
The syntax of the function which returns a reference in c++ is, data_type& function_name(data_type& original_variable){ // perform any actions to the original variable. So the return of the function will be a reference to a (part of) local. Int func3() { return 1;
But There Is A Way To Access The Local Variables Of A Function Using Pointers, By Creating Another Pointer Variable That Points To.
You cannot return a reference to a local variable, as the variable will cease to exist once the function terminates. } int main() { int v = func3(); When find1 function returns, object final is destroy.
In Either Case, You Can Just Return The Value Itself (Although I Realize The Example You Provided Was Probably Contrived):
You are returning a reference to a local variable. In a case like this, you should really return a value. Returning a reference to a local or temporary variable;
In Program Above, The Return Type Of Function Test () Is Int&.
So p would not be copied. I guess g++ and visual c++ choose to implement the undefined state in this case as trying to get the value of the reference to local variable thereby making b has the. Returning const reference to local variable from a function;
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